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Let x ( n ) be a sequence of length 1024 that is to be convolved with a sequence h ( n ) of length L. For what values of L is it more efficient to perform the convolution directly than it is to perform the convolution by taking the inverse DFT of the product X (k)H ( k ) and evaluating the DFTs using a radix-2 FFT algorithm

PRINCIPLE 12:

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Suppose that we have a 1025-point data sequence (1 more than N = 2"). Instead of discarding the final value, we zero pad the sequence to make it of length N = 2" so that we can use a radix-2 FFT algorithm. (a) How many multiplications and additions are required to compute the DFT using a radix-2 FFT algorithm (b) How many multiplications and additions would be required to compute a 1025-point DFT directly

7.19 7.20 7-21

5.7 Applying algebra to the rhombus Assuming ABCD is a rhombus, find x and y in each part of Fig. 5-18.

Fig. A-17

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In a radix-3 decimation-in-time FFT, how is the input sequence indexed How many complex multiplications are necessary in a radix-3 decimation-in-frequency FFT Consider the FFT algorithm given in Example 7.3.2. ( a ) How many multiplications and additions are required to compute a 12-point DFT (h) How many multiplications and additions are necessary if the 12-point DFT is computed directly

Fig. 5-18

7.22 7.23

(a) Since AB > AD, 3x (b) Since BC > AB, 5y 7 6 20 or x y 9. Since nABD is equiangular it is equilateral, and so y 31. 2 Since CD > BC, x y 20 or x 231. 2 2(35 ) 70 . 20.

Find the index maps for a 99-point prime factor FFT with N I = I I and N2 = 9. How many complex multiplications are required for a 12-point prime factor FFT with N, = 4 and N3 = 3 if we do not count multiplications by + I and j

PROOF:

7.24 7.25

3 3 5 11 3 ; (b) ; (c) ; (d) ; (e) ; (f) . 4 4 2 3 6 2

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How many twiddle factors are there in a 99-point prime factor FFT with N I = I 1 and N2 = 9 How many complex multiplications are required for a 15-point prime factor FFT if we do not count multiplications by & I

1. 2. 3. 4. 5. 6. 7.

7.18 7.19 7.20 7.21

Reasons 1. 2. 3. 4. 5. 6. 7. Given Given A midpoint divides a line into two congruent parts. A rectangle is equiangular. Opposite sides of a ~ are congruent. SAS s Corresponding parts of congruent n are congruent.

(a) 1 1.264. (b) 1,050,625. The index for x(n) is expressed in ternary form, and then the ternary digits are read in reverse order. The same as a decimation-in-time FFT, which is 2N log, N . (a) Each 4-point DFT requires no multiplies and 12 adds, and each 3-point DFT requires 6 multiplies and 6 adds. With 6 twiddle factors, there are 6 (4)(6) = 30 multiplies and (4)(6) (3)(12) = 60 adds. (b) 144 multiplies and 132 adds.

5.9 Proving a special parallelogram problem stated in words Prove that a diagonal of a rhombus bisects each vertex angle through which it passes.

25.12 (a)

7.22 7.23 7.24 7.25

Rhombus ABCD AC is a diagonal. To Prove: AC bisects /A and /C. Plan: Prove (1) /1 and /2 are congruent to /3. (2) /3 and /4 are congruent to /1.

8

Given a linear shift-invariant system with a rational system function H ( z ) , the input and output are related by a linear constant coefficient difference equation. For example, with a system function

PROOF:

1)-bit numbers is rounded to B I bits before any additions are performed, find the variance of the round-off noise at the output of the filter.

Given:

26.7 (a)

IMPLEMENTATION OF DISCRETE-TIME SYSTEMS (a) The system function for a pth-order allpass filter has the form

1. 2. 3. 4. 5. 6. 7.

H (z) =

Statements ABCD is a rhombus. AB > BC /1 > /3 BC i AD, AB i CD /2 > /3, /1 > /4 /1 > /2, /3 > /4 AC bisects /A and /C.

a(p)

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